Google CodeJam – Mushroom Monster

Question URL is https://code.google.com/codejam/contest/4224486/dashboard

This question could be become two sub question.
1. less mushroom to eat.
for array 10 5 15 5, what is the sum of decreased numbers?
10 is decreased to 5, the decreased number is (10-5).
5 raises to 15, it will be ignored.
15 is decreased to 5, the decreased number is (15-5)

the sum of all decreased numbers that is (10-5)+(15-5) will be the answer.

2. eating mushroom in static speed.

find the max gap of decreased numbers. (15-5) is the max speed in 10 seconds.
there for, if mushroom number on the dish is greater than (15-5), Kaylin only eats(15-5).

if mushroom number on the dish is less that (15-5), Kaylin will finish all of them and waiting for next refill.

Here is Clang code.

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
  int N;
  int L;
  int i,j,k;
  int array[MAXSIZE];
  int sum1 = 0;
  int sum2 = 0;
 
  scanf("%d\n",&N);
 
  for(i=0;i<N;i++)
  {
    scanf("%d",&L);
    memset(array,0,sizeof(int)*MAXSIZE);
    sum1 = 0;
    sum2 = 0;
    for(j = 0;j<L;j++){
      scanf("%d",&array[j]);
    }
 
    //start
    for(j = 0;j<L - 1;j++){
      if(array[j]>array[j + 1])
        sum1 += (array[j] - array[j + 1]); 
    }
 
    int max = 0;
 
    for(j = 0;j<L - 1;j++){
      if(array[j]>array[j + 1]){
        if(max<(array[j] - array[j + 1])){
          max = array[j] - array[j + 1];
        }
      }
    }
 
    for(j = 0;j<L - 1;j++){
      sum2 += (array[j]>max?max:array[j]); 
    }
 
    printf("Case #%d: %d %d\n",(i + 1),sum1,sum2);
  }