# Google CodeJam – Mushroom Monster

This question could be become two sub question.
1. less mushroom to eat.
for array 10 5 15 5, what is the sum of decreased numbers?
10 is decreased to 5, the decreased number is (10-5).
5 raises to 15, it will be ignored.
15 is decreased to 5, the decreased number is (15-5)

the sum of all decreased numbers that is (10-5)+(15-5) will be the answer.

2. eating mushroom in static speed.

find the max gap of decreased numbers. (15-5) is the max speed in 10 seconds.
there for, if mushroom number on the dish is greater than (15-5), Kaylin only eats(15-5).

if mushroom number on the dish is less that (15-5), Kaylin will finish all of them and waiting for next refill.

Here is Clang code.

```1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 int N; int L; int i,j,k; int array[MAXSIZE]; int sum1 = 0; int sum2 = 0;   scanf("%d\n",&N);   for(i=0;i<N;i++) { scanf("%d",&L); memset(array,0,sizeof(int)*MAXSIZE); sum1 = 0; sum2 = 0; for(j = 0;j<L;j++){ scanf("%d",&array[j]); }   //start for(j = 0;j<L - 1;j++){ if(array[j]>array[j + 1]) sum1 += (array[j] - array[j + 1]); }   int max = 0;   for(j = 0;j<L - 1;j++){ if(array[j]>array[j + 1]){ if(max<(array[j] - array[j + 1])){ max = array[j] - array[j + 1]; } } }   for(j = 0;j<L - 1;j++){ sum2 += (array[j]>max?max:array[j]); }   printf("Case #%d: %d %d\n",(i + 1),sum1,sum2); }```