# LeetCode OJ: Length of Last Word

### Length of Last Word

Total Accepted: 29154 Total Submissions: 100944

Given a string s consists of upper/lower-case alphabets and empty space characters `' '`, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = `"Hello World"`,
return `5`.

https://oj.leetcode.com/problems/length-of-last-word/

Solution: see the comment in the code , writed in Java

```1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29   public static int lengthOfLastWord(String s) { if(s.length() == 0) return 0; // input may be ""   int result = -1;   int skipEmpty = 0; // skip empty string at the end of input string s for(int i= s.length() - 1;i>=0;i--) { if(s.charAt(i) == ' ') continue; else { skipEmpty = i; break; } } //Start to Calculate for(int i= skipEmpty;i>=0;i--) { if(s.charAt(i) != ' ') continue; else { result = i; break; }   }   return skipEmpty - result; }```